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[ By Tonnny @ ptt]

// 如此可產生n*m的array.....
// n,m可由使用者輸入!
// 重點是,此array可以在functions內使用
#include

void main(){

int n;
int m;
cin >> n >> m;

int **a=(int **)new int*[n];
for (int i = 0; i < n; i++)
{
*a(m+i)=(int *)new int[i][m];
}

for (int k = 0; k < n; k++){
for (int j = 0;j < m; j++)
{
a[k][j] = 0;
}
}
for (i = 0; i < n; i++)
{
delete [] a[i];
}

delete [] a;
}